SOLUTION: Help would be appreciated Mindy left at 8am and arrived at 1pm. Kelly left at 8am and arrived at 2pm. How many miles wasthe trip if kelly traveled 10 miles per hour SLOWER than

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Question 63628This question is from textbook An Incremental Development
: Help would be appreciated
Mindy left at 8am and arrived at 1pm. Kelly left at 8am and arrived at 2pm. How many miles wasthe trip if kelly traveled 10 miles per hour SLOWER than mindy?
Thank you! This question is from textbook An Incremental Development

Answer by joyofmath(189) About Me  (Show Source):
You can put this solution on YOUR website!

Mindy left at 8am and arrived at 1pm. Kelly left at 8am and arrived at 2pm. How many miles was the trip if kelly traveled 10 miles per hour SLOWER than mindy?
Let Mindy's speed, in miles per hour, = S%5Bm%5D.
Let Kelly's speed, in miles per hour, = S%5Bk%5D.
Let Mindy's time = T%5Bm%5D+=+5.
Let Kelly's time = T%5Bk%5D+=+4.
Speed x Time = Distance.
The distance covered by both was the same. Call it D.
So, D=S%5Bm%5D%2AT%5Bm%5D+=+S%5Bm%5D%2A5.
And D=S%5Bk%5D%2AT%5Bk%5D+=+S%5Bk%5D%2A6.
So, S%5Bm%5D%2A5+=+S%5Bk%5D%2A6.
We are told that Kelly traveled 10mph slower than Mindy, so S%5Bm%5D=S%5Bk%5D%2B10.
So, %28S%5Bk%5D%2B10%29%2A5+=+S%5Bk%5D%2A6.
Or, 5%2AS%5Bk%5D%2B50+=+S%5Bk%5D%2A6.
Subtract 5S%5Bk%5D from both sides: 50=S%5Bk%5D.
So, Kelly traveled at 50 mph and Mindy traveled 10 mph faster at 60 mph.
The distance traveled is 50 mph * 6 hours (Kelly's speed and time) = highlight%28300+miles%29.
Nore that Mindy's speed * Mindy's time = 60 mph * 5 hours = 300 miles also.