Question 636255: the tens digit of a certain number is 3 more than the one digit. The sum of the squares of the digits is 29. find the number. Answer by sachi(548) (Show Source):
You can put this solution on YOUR website! the tens digit of a certain number is 3 more than the one digit. The sum of the squares of the digits is 29. find the number.
ans:-
let the ones digit is x
then tens digit is x+3
as per question x^2+(x+3)^2=29
or 2x^2+6x-20=0
or 2x^2+10x-4x-20=0
or 2x(x+5)-4(x+5)=0
or (2x-4)(x+5)=0
or x=-5 or 2 ans
