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Question 636213: x2-49/2x-1 x2-14x+49/1-2x
x2-49 should be the numerator and the 2x-1 is the denominator.
x2-14x+49 is the numerator and the 1-2x is the denominator.
Find the domain of each of the rational expressions. (Identify which values of x will make the denominator zero and thus are not allowed in the domain.)
Divide your first rational expression by the second one. Write the answer in lowest terms.
Find and state the common denominator between the two expressions. Build up each expression so that it has the common denominator. (Remember not to do any canceling at this point since you need those extra factors for the common denominator.)
Add the two rational expressions together. Factor again if possible, and present the answer in lowest terms.
Incorporate the following five math vocabulary words into your discussion. Use bold font to emphasize the words in your writing (Do not write definitions for the words; use them appropriately in sentences describing your math work.):
Domain
Lowest terms
Opposites
LCD
Build up
thank you for any help you can give. I tried this but I dont seem to get it.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! (x^2-49)/(2x-1)
Domain: All Real Numbers except x = 1/2
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(x^2-14x+49)/(1-2x) = (x^2-14x+49)/(-(2x-1))
Factor:
(x-7)^2/(1-2x)
Domain: All Real Numbers except x = 1/2
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Least common denominator:
(-(2x-1)
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Dividing:
[(x^2-49)/(2x-1)]/[(x^2-14x+49)/(-(2x-1))]
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[(x-7)(x+7)/(2x-1)]/[(x-7)^2/(-(2x-1)]
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Invert the denominator and multiply:
[(x-7)(x+7)/(2x-1)]
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Cancel factors that are common to a numerator and a denominator:
[(x+7)/1]
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= -(x+7)/(x-7)
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Cheers,
Stan H.
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