SOLUTION: Please help. Completely lost... In how many ways can the letters in the word TRANSPORTATION be arranged if the first letter must be an A and the last letter must not be a T?

Algebra ->  Probability-and-statistics -> SOLUTION: Please help. Completely lost... In how many ways can the letters in the word TRANSPORTATION be arranged if the first letter must be an A and the last letter must not be a T?       Log On


   



Question 636129: Please help. Completely lost...
In how many ways can the letters in the word TRANSPORTATION be arranged if the first letter must be an A and the last letter must not be a T?
Would really appreciate it

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The first letter must be an A. So the word looks like

A _ _ _ _ _ _ ...

So you're really arranging 14-1 = 13 letters in 13 slots

The last letter must not be a T. So you have 13-1 = 12 choices for the last slot

The other slots go like this:

You have 13-1 = 12 choices for the second slot (after you choose a letter that is not T for the last slot)

You have 12-1 = 11 choices for the third slot

You have 11-1 = 10 choices for the fourth slot

etc
etc

all the way down to

You have 2 choices for the second to last slot

You have 1 choice for the last slot

Multiply all these choices out:

12*12*11*10*9*8*7*6*5*4*3*2*1 = 5748019200

Now divide by 2!*2!*3! = 4*4*6 = 96 to get 5748019200/96 = 59,875,200

This is to correct for the duplicates

So there are 59,875,200 ways to arrange the letters.


Note: if you are entering this into an online system, then chances are that you'll have to enter the number WITHOUT commas