SOLUTION: If an object is thrown upward with an initial velocity of 112ft/sec, it's height after t sec is given by h=112t-16t^2. how long will it take for the object to reach it's maximum h

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Question 636125: If an object is thrown upward with an initial velocity of 112ft/sec, it's height after t sec is given by h=112t-16t^2. how long will it take for the object to reach it's maximum height?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

 h=  -16t^ + 112t    Note: 112%2F2%2A16+=+7%2F2

 h =  -16(t-7/2)^2 + 16*49/4

  h =  -16(t-7/2)^2 + 196  



Note: vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk 

where(h,k) is the vertex  



Parabola opening Downward  V(3.5,196)

how long will it take for the object to reach it's maximum height?  

 will take 3.5 sec to reach max height of 196 ft