SOLUTION: How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

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Question 635848: How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
How much pure water must be mixed with 10 liters of a 25% acid solution to
reduce it to a 10% acid solution?
:
let w = amt of water required to accomplish this
:
The amt of acid will remain the same only the water will increase, lowering the percent
:
.25(10) = .10(w+10)
2.5 = .10w + 1
2.5 - 1 = .1w
1.5 = .1w
w = 1.5%2F.1
w = 15 liters of water
:
:
Confirm this
.25(10) = .10(25)