SOLUTION: 60 ml of solution A is mixed with 120 ml of solution B to produce solution C which contains 8% of pure acid. If 80 ml of solution A is mixed with 40 ml of solution B, a solution D
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Question 635813: 60 ml of solution A is mixed with 120 ml of solution B to produce solution C which contains 8% of pure acid. If 80 ml of solution A is mixed with 40 ml of solution B, a solution D containing 10% of pure acid can be produced. Find the percentage of pure acid in solution A. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! 60 ml of solution A is mixed with 120 ml of solution B to produce solution C which contains 8% of pure acid. If 80 ml of solution A is mixed with 40 ml of solution B, a solution D containing 10% of pure acid can be produced. Find the percentage of pure acid in solution A.
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let x=% acid in solution A
let y=% acid in solution B
2 equations:
60x+120y=.08(60+120)=.08(180)=14.4
80x+40y=.10(80+40)=.10(120)=12
..
60x+120y=14.4
80x+40y=12
..
60x+120y=14.4
240x+120y=36
subtract
-180x=-21.6
x=21.6/180=.12
40y=12-80x=12-.12*80=2.4
y=2.4/40=.06
percentage of pure acid in solution A=12%
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