Question 635722: solve 7^(x^2)=2^(x+1) for x
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve 7^(x^2)=2^(x+1) for x
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log2(7) = log(7)/log(2) = 2.8074
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Resrite the problem:
[2^2.8074)^(x^2) = 2^(x+1)
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2^(2.8074x^2) = 2^(x+1)
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2.8074x^2 = x+1
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2.8074x^2 - x - 1 = 0
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x = -0.4447... or x = 0.8009...
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Cheers,
Stan H.
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