SOLUTION: Two ocean liners leave from the same port in Puerto Rico at 10:00 a.m. One travels at a bearing of
N 46°W at 12 miles per hour, and the other travels at a bearing of S 55°W at 14
Algebra ->
Trigonometry-basics
-> SOLUTION: Two ocean liners leave from the same port in Puerto Rico at 10:00 a.m. One travels at a bearing of
N 46°W at 12 miles per hour, and the other travels at a bearing of S 55°W at 14
Log On
Question 635545: Two ocean liners leave from the same port in Puerto Rico at 10:00 a.m. One travels at a bearing of
N 46°W at 12 miles per hour, and the other travels at a bearing of S 55°W at 14 miles per hour.
Approximate the distance between them at noon the same day. Round answer to two decimal places.
You can put this solution on YOUR website! Two ocean liners leave from the same port in Puerto Rico at 10:00 a.m. One travels at a bearing of
N 46°W at 12 miles per hour, and the other travels at a bearing of S 55°W at 14 miles per hour.
Approximate the distance between them at noon the same day. Round answer to two decimal places.
=========================
N46W = 314 degs
S55W = 235 degs
No one in the world uses N46W or S55W except the authors of math books who never go outside.
------------------------
The angle between their paths is 79 degs
The distances are 24 & 28 miles
----------
Use the Cosine Law
