SOLUTION: After leaving the runway, a plane's angle of ascent is 16° and its speed is 267 feet per second. How many minutes will it take for the airplane to climb to a height of 12,500 feet?
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Question 635543: After leaving the runway, a plane's angle of ascent is 16° and its speed is 267 feet per second. How many minutes will it take for the airplane to climb to a height of 12,500 feet? Round answer to two decimal places. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Vertical height = 12500
distance traveled by the plane = x
sin 16 = 12500/x
x= 12500/sin 16
x= 45349.4 feet
r= 267 ft/s
t= 45349.4/267
t= 169.85 seconds
3.40 minutes
