SOLUTION: Twenty-six small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 44.5 ca

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Question 635420: Twenty-six small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 44.5 cases per year.
(a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
lower limit =
upper limit =
margin of error =
(b) Find a 95% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)

lower limit =
upper limit =
margin of error =
(c) Find a 99% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
lower limit =
upper limit =
margin of error =

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Note: z-values for various confidence levels
90% z = 1.645
95% z = 1.96
98% z = 2.33
99% z = 2.576
a) ME = 1.645(44.5/sqrt(10000)= .732
138.5 - ME < mu < 138.5 + ME
b)ME = 1.96(44.5/sqrt(10000)= .873
138.5 - ME < mu < 138.5 + ME
c)ME = 2.576(44.5/sqrt(10000)= 1.146
138.5 - ME < mu < 138.5 + ME