SOLUTION: Two automobiles set out simultaneously from places 100 miles apart . They traveled toward each other and passed at the end of 1 hour and 40 minutes. The speed of one automobile

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Question 635390: Two automobiles set out simultaneously from places 100 miles apart . They traveled toward each other and passed at the end of 1 hour and 40 minutes. The speed of one automobile was 5 miles per hour greater than that of the other. Find the speed of each?
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
The slower traveled at x miles per hour
The faster traveled at x+5 miles per hour

Their approach rate = the sum of their speeds = x+(x+5) = x+x+5 = 2x+5

Time = 1 hour 40 minutes = 1%2640%2F60 hours = 1%262%2F3 hours = 5%2F3 hours.

Distance = (Rate)·(Time)
     100 = (2x+5)·5%2F3

Multiply through by 3

     300 = (2x+5)·5

Divide both sides by 5
    
      60 = 2x+5
      55 = 2x
    27.5 = x

The slower was going 27.5 miles per hour and the faster was going
5 miles per hour faster or 32.5 miles per hour.

Edwin