SOLUTION: solve the systems of equations by substitution y = 8 - 3x/2 y = 3x/4 -1

Algebra ->  Equations -> SOLUTION: solve the systems of equations by substitution y = 8 - 3x/2 y = 3x/4 -1      Log On


   

Question 635307: solve the systems of equations by substitution y = 8 - 3x/2
y = 3x/4 -1
Answer by Maths68(1474) About Me  (Show Source):
You can put this solution on YOUR website!
y=8-3x%2F2...............(1)
y=3x%2F4-1...............(2)
Substitute the value of y from (1) to (2)
8-3x%2F2=3x%2F4-1
%2816-3x%29%2F2=%283x-4%29%2F4
%284%29%2816-3x%29%2F2=3x-4
cross%284%29%2816-3x%29%2Fcross%282%29=3x-4
%282%29%2816-3x%29=3x-4
32-6x=3x-4
-6x-3x=-4-32
-9x=-36
-9x%2F-9=-36%2F-9
cross%28-9%29x%2Fcross%28-9%29=cross%28-36%29%2Fcross%28-9%29
x=4
Put the value of x in (1)
y=8-3x%2F2...............(1)
y=8-3%284%29%2F2
y=8-12%2F2
y=8-cross%2812%29%2Fcross%282%29
y=8-6
y=2
x,y=4,2


Check
=====
Put the value of x and y in (1)
y=8-3x%2F2...............(1)
2=8-3%284%29%2F2
2=8-12%2F2
2=8-cross%2812%29%2Fcross%282%29
2=8-6
2=2
Put the value of x and y in (2)
y=3x%2F4-1...............(2)
2=3%284%29%2F4-1
2=3cross%284%29%2Fcross%284%29-1
2=3-1
2=2