SOLUTION: A cubic polynomial equation with real coefficients has two zeros, 5 and 6 + 2i. Which of the following is the polynomial equation? Which answer is it? a. -x^3 - 17x^2 + 100x

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: A cubic polynomial equation with real coefficients has two zeros, 5 and 6 + 2i. Which of the following is the polynomial equation? Which answer is it? a. -x^3 - 17x^2 + 100x       Log On


   

Question 635232: A cubic polynomial equation with real coefficients has two zeros, 5 and 6 + 2i. Which of the following is the polynomial equation?
Which answer is it?
a. -x^3 - 17x^2 + 100x + 200 = 0
b. x^3 + 17x^2 + 100x + 200 = 0
c. x^3 - 17x^2 + 100x - 200 = 0
d. x^3 - 17x^2 - 100x - 200 = 0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

A cubic polynomial equation with real coefficients has two zeros, 5 and 6 + 2i.

 x^3 - 17x^2 + 100x - 200 = 125 - 425 + 500-200 = 0

 5	1	-17	100	-200

 	 	  6	-60	 200

 	1	-12	40	0

(x^2 - 12x + 40)

x+=+%2812+%2B-+sqrt%28+-16+%29%29%2F%282%29+ 

x+=+6+%2B-+2i+