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xイ-2x-35
覧覧覧覧覧
x+5
There are 3 ways to do it, depending on
where you are in the book.
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Method 1: Long division:
x - 7
x + 5)xイ - 2x - 35
xイ + 5x
-7x - 35
-7x - 35
0
So the answer is the quotient x - 7
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Method 2: Synthetic division:
_________
-5|1 -2 -35
| -5 35
1 -7 0
So the answer is x - 7
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Method 3: Factoring and canceling:
xイ-2x-35
覧覧覧覧覧
x+5
Factor the trinomial numerator.
xイ-2x-35
(x )(x )
Think of two integers whose product is 35
and whose difference is 2. They are 7 and 5
(x 7)(x 5)
Then since the 7 is larger it gets the same
sign as the -2x or -, and the 5 gets the
opposite sign, +
(x-7)(x+5)
So the fraction
xイ-2x-35
覧覧覧覧覧
x+5
becomes
(x-7)(x+5)
覧覧覧覧覧覧
x+5
Now cancel the x+5 in the
denominator into the (x+5)
in the numerator:
1
(x-7)(x+5)
覧覧覧覧覧覧
x+5
1
This leaves
(x-7)
or just
x - 7
Edwin