SOLUTION: (2-5i)^2
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Question 634980
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(2-5i)^2
Answer by
ankor@dixie-net.com(22740)
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(2-5i)^2
FOIL (2-5i)(2-5i)
4 - 10i - 10i + 25i^2
4 - 20i + 25(-1)
4 - 20i - 25 = -21 - 20i