SOLUTION: Solve the following system of equations and check. Either an algebraic or graphic method will be accepted. x²+y²=25 3x-4y=0

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Question 634679: Solve the following system of equations and check. Either an algebraic or graphic method will be accepted.
x²+y²=25
3x-4y=0
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the following system of equations and check. Either an algebraic or graphic method will be accepted.
x²+y²=25
3x-4y=0
------------
3x-4y = 0
y = 3x/4
Sub for y in the circle eqn
----------
x%5E2+%2B+%283x%2F4%29%5E2+=+25
25x%5E2%2F16+=+25
x%5E2+=+16
You can finish and check, right?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

3x-4y=0  OR = y = (3/4)x

x%5E2+%2B%28+9%2F16%29x%5E2+=+25

x%5E2%2825%2F16%29+=+25

    x^2 = 16

    x = ± 4   and y = ± 3

(4,3) and (-4,-3) the solutions to this system of EQs