SOLUTION: A cattleman sold 60 calves and 240 sheep for $17, 160; and, the pricing the animals in the same way, he sold 40 calves and 180 sheep to other buyer for $12,240. Find the price per

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: A cattleman sold 60 calves and 240 sheep for $17, 160; and, the pricing the animals in the same way, he sold 40 calves and 180 sheep to other buyer for $12,240. Find the price per       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 634526: A cattleman sold 60 calves and 240 sheep for $17, 160; and, the pricing the animals in the same way, he sold 40 calves and 180 sheep to other buyer for $12,240. Find the price per head for each kind of animals.
Answer by Maths68(1474) About Me  (Show Source):
You can put this solution on YOUR website!
Let
Price of a calf = c
Price of a Sheep = s
60c+240s=17160................(1)
40c+180s=12240................(2)

Multiply (1) by 40 and (2) -60 and Add
2400c+9600s=686400
-2400c-10800s=-734400
-----------------------
-1200s=-48000
-1200s/-1200=-48000/-1200
s=40
Put the value of s in (1)
60c+240s=17160................(1)
60c+240(40)=17160
60c+9600=17160
60c=17160-9600
60c=7560
60c/60=7560/60
c=126

Price of a calf = c = $126
Price of a Sheep = s = $40