SOLUTION: You have 15L of 24% acid solution. How much water should you add in order to dilute the solution so that it is 8% acid?

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Question 634479: You have 15L of 24% acid solution. How much water should you add in order to dilute the solution so that it is 8% acid?
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +w+ = liters of water to be added
+.24%2A15+=+3.6+ liters of acid in 24% solution
+3.6+%2F+%28+w+%2B+15+%29+=+.08+
+3.6+=+.08%2A%28+w+%2B+15+%29+
+3.6+=+.08w+%2B+1.2+
+.08w+=+3.6+-+1.2+
+.08w+=+2.4+
+w+=+30+
30 liters of water should be added
check:
+3.6+%2F+%28+30+%2B+15+%29+=+.08+
+3.6+%2F+45+=+.08+
+3.6+=+.08%2A45+
+3.6+=+3.6+
OK

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
You have 15L of 24% acid solution. How much water should you add in order to dilute the solution so that it is 8% acid?
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Equation:
water + water = water
0.76*15 + x = 0.92(15+x)
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Multiply thru by 100 to get:
76*15 + 100x = 92*15 + 92x
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8x = 16*15
x = 30L (amt. of water to add)
Cheers,
Stan H.