SOLUTION: I need help please with this problem. Find the vertical asymptote for x/x^2-36

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Question 634477: I need help please with this problem. Find the vertical asymptote for x/x^2-36
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Set the denominator equal to zero and solve

x%5E2-36=0

%28x%2B6%29%28x-6%29=0

x%2B6=0 or x-6=0

x=-6 or x=6


So the vertical asymptotes are x=-6 and x=6