SOLUTION: I need help please with this problem. Find the horizontal asymptote for x^4/x-10

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Question 634475: I need help please with this problem. Find the horizontal asymptote for x^4/x-10
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
A general rule for horizontal asymptotes is:
  • If the degree of the numerator is less than the degree of the denominator, then the horizontal asymptote will be y = 0
  • If the degree of the numerator equals the degree of the denominator, then the horizontal asymptote will be y = a/b where "a" is the coefficient of the highest term of the numerator and "b" is the coefficient of the highest degree term in the denominator. So for
    %2812x%5E3-3x%5E2%2B120x-1000%29%2F%2818x%5E3%2B200x%5E2-23x-4%29
    The degrees are 3's and the "a" is 12 and the "b" is 18. So the horizontal asymptote would be:
    y+=+12%2F18 which reduces to y+=+2%2F3
  • If the degree of the numerator is greater than the degree of the denominator, then there is no horizontal asymptote. (There will, however, be an asymptote that is not horizontal or vertical.)
Your numerator's degree is 4 and your denominator's degree is 1. So there will not be a horizontal asymptote.