You can put this solution on YOUR website! log (2x+1) base 2 - log (x-1) base 2 = 3
place under single log base 2
log2[(2x+1)/(x-1)]=3
Convert to exponential form: base(2) raised to log of number(3)=number(2x+1)/(x-1)
2^3=(2x+1)/(x-1)=8
8(x-1)=2x+1
8x-8=2x+1
6x=9
x=9/6=3/2=1.5
..
Check:
log (2*1.5+1) base 2 - log (1.5-1) base 2 = 3
log2(4)-log2(.5)=4-1=3
You can put this solution on YOUR website! log (2x+1) base 2 - log (x-1) base 2 = 3
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log2[(2x+1)(x-1)] = 3
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(2x+1)(x-1) = 2^3
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2x^2 -x -1 = 8
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2x^2 -x -9 = 0
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x = [1 +- sqrt(1-4*2*-9)]/4
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Positive solution:
x = [1+ sqrt(73)]/4
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x = 2.386...
Cheers,
Stan H.
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