SOLUTION: Hello. I got these questions and I really could use some help.
1. 6e^(1-x)+1 = 21
2. 4x + 2e^(2y) -8 = 0.
Withe the first one, I got as far as the fraction:
lne^(1-x) = ln
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-> SOLUTION: Hello. I got these questions and I really could use some help.
1. 6e^(1-x)+1 = 21
2. 4x + 2e^(2y) -8 = 0.
Withe the first one, I got as far as the fraction:
lne^(1-x) = ln
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Question 634412: Hello. I got these questions and I really could use some help.
1. 6e^(1-x)+1 = 21
2. 4x + 2e^(2y) -8 = 0.
Withe the first one, I got as far as the fraction:
lne^(1-x) = ln 20/6
Please help. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 1. 6e^(1-x)+1 = 21
e^(1-x) = 20/6 = 10/3
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ln(e^xyz) = xyz
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1-x = ln(10/3)
x = 1 - ln(10/3)
x =~ -0.2039728
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2. 4x + 2e^(2y) -8 = 0
What do you want to do with this one?
