SOLUTION: Find the area between the curves y=x^2 -3x and y=-x

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Question 634064: Find the area between the curves y=x^2 -3x and y=-x
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the area between the curves y=x^2 -3x and y=-x
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The intersections are at x = 0 and x = 2
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INT(x^2 - 3x) = x^3/3 - 3x^2/2
@2 = 8/3 - 6 = -10/3
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INT(-x) = -x^2/2
@2 = -2
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Area = ABS of the difference
Area = 10/3 - 2 = 4/3 sq units

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
int%28+%28x%5E2+-+3x%29%2C+dx%2C+0%2C+2%29 = x%5E3%2F3+-+%283%2F2%29x%5E2+=+8%2F3+-+6+=+8%2F3+-+18%2F3+=+-10%2F3+=+-3%261%2F3
int%28%28-x%29%2C+dx%2C+0%2C+2%29 =+-x%5E2%2F2+=+-2
-1%261%2F3 is the Area between the curves