SOLUTION: A rectangular lot is 20 m by 32 m. A circular gazebo of diameter of 7 m is placed on the lot. How much of the lot is left?

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Question 63395: A rectangular lot is 20 m by 32 m. A circular gazebo of diameter of 7 m is placed on the lot. How much of the lot is left?
Found 2 solutions by Cintchr, jai_kos:
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
Area of the rectangle - area of the circle = what is left
+%28l%2Aw%29+-+%28pi%29r%5E2+=+A+
DO NOT plug in 3.14 for pi unless your teacher tells you to
l = 20
w = 32
r = 3.5
+%2820%2A32%29+-+%28pi%293.5%5E2+=+A+
+640+-+%28pi%2912.25+=+A+
Now, if they want you to plug in pi ... do it at this step
+640+-+%28pi%2912.25+=+A+
+640+-+38.465+=+A+
+601.535+=+A+

Answer by jai_kos(139) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangular lot is 20 m by 32 m. A circular gazebo of diameter of 7 m is placed on the lot. How much of the lot is left?
Solution:
A rectangular plot is 20m by 32m.

The area of the rectangular plot is length * breadth = 20 *32 = 640.
Given the diameter of a circular gazebo is 7m .
Therefoer the radius = diameter /2 = 7 / 2 = 3.5m
The area of the circle = pi r^2 = pi * 3.5 ^2 = 3.14 * 3.5 *3.5 = 38.465
The left over plot = Rectangular plot area - area of the radius = 640 - 38.465
= 601.535m