Question 633839: please, solve 1/3log(x)-log10,000=4
my email is, martaayele@yahoo.com
Found 2 solutions by lwsshak3, solver91311:
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! please, solve 1/3log(x)-log10,000=4
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1/3log(x)-log10,000=4
1/3log(x)-4=4
1/3log(x)=8
log (x^1/3)=8
x(1/3)=10^8 (exponential form)
cube both sides
x=10^24
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the other question, is application of growth and decay.
here is the question, the half life of uranium,is 2.52(10^5)year. if 97.7% of the uranium in the original sample is present, what length of time is elapsed?(to the nearest thousand years.)
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Formula for radioactive decay: A/Ao=2^-t/h, A=radioactive material present at time t, Ao=amt present initially, h=material half life.
.977=2^-t/2.52*10^5
take log of both sides
log.977=(-t/2.52*10^5)log2
(log.977)*(2.52*10^5)/log2=-t
-t≈-8460
length of time elapsed≈8000 years
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solve this expression in terms of ln(x),
e^x=9
take log of both sides
xlne=ln9
lne=1
x=ln9
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contract this expression
ln(3)-2(ln(4)+ln(8)
=ln[3*8/4^2]
=ln[24/16]
=ln[3/2]
=ln[1.5]
Answer by solver91311(24713)  (Show Source):
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