SOLUTION: I have to write the equation of a line parallel to the given line but passing through the give point.
y = -x + 3; (-2,-2)
then I have to write the equation of a line perpendicula
Algebra ->
Linear-equations
-> SOLUTION: I have to write the equation of a line parallel to the given line but passing through the give point.
y = -x + 3; (-2,-2)
then I have to write the equation of a line perpendicula
Log On
Question 633811: I have to write the equation of a line parallel to the given line but passing through the give point.
y = -x + 3; (-2,-2)
then I have to write the equation of a line perpendicular to the given line but not passing through the given point.
y = -2/3x +2; (9,3)
I am so twisted by the ways to solve this I am vapor locked on how to complete this. If you can, just show me how to solve the equations with similar factors and I can probably work it out by seeing them. Answer by solver91311(24713) (Show Source):
In either case, you first must determine the slope of the given line. Since both of the given equations are in slope intercept form, you can do this by inspection of the coefficient on .
Then you need to determine the slope of the desired line. In the parallel case use: Parallel lines have identical slopes.
In the perpendicular case use: Perpendicular lines have negative reciprocal slopes.
Then you need to use the point-slope form of an equation of a line to derive the desired equation.
where are the coordinates of the given point and is the given or calculated slope.
John
My calculator said it, I believe it, that settles it
