SOLUTION: the total resistance R of two resistors in parallel is given by R=1/1/R1(the 1 is little and below the R) +1/R2(2 is also tiny) where R1(1 tiny) is the resistance of the first and
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: the total resistance R of two resistors in parallel is given by R=1/1/R1(the 1 is little and below the R) +1/R2(2 is also tiny) where R1(1 tiny) is the resistance of the first and
Log On
Question 633804: the total resistance R of two resistors in parallel is given by R=1/1/R1(the 1 is little and below the R) +1/R2(2 is also tiny) where R1(1 tiny) is the resistance of the first and R2(2 tiny) the resistance of the second. Solve that equation for R1(1 tiny) and simplify.
Please help.. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! R = 1/[(1/R1) + (1/R2)]
----
R = 1/[(R2+R1)/(R1*R2)]
-----
R = R1*R2/(R1 + R2)
===========================
Cheers,
Stan H.
=============
(