SOLUTION: Solve √(x+1)+5=x+4

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Question 633773: Solve
√(x+1)+5=x+4

Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve
√(x+1)+5=x+4
----
sqrt(x+1) = x-5
---
Square both sides to get:
x+1 = x^2 - 10x +25
x^2 -11x + 24 = 0
---
Factor:
x^2 - 3x - 8x + 24 = 0
x(x-3) - 8(x-3) = 0
----
(x-3)(x-8) = 0
----
x = 3 or x = 8
================
Cheers,
Stan H.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Solve
√(x+1)+5=x+4

sqrt%28x+%2B+1%29+%2B+5+=+x+%2B+4

sqrt%28x+%2B+1%29+=+x+%2B+4+-+5 --- Subtracting 5

sqrt%28x+%2B+1%29+=+x+-+1

%28sqrt%28x+%2B+1%29%29%5E2+=+%28x+-+1%29%5E2 ------ Squaring both sides of equation

x+%2B+1+=+x%5E2+-+2x+%2B+1

x%5E2+-+2x+-+x+%2B+1+-+1+=+0

x%5E2+-+3x+=+0

x(x - 3) = 0

x = 0 or x - 3 = 0

x+=+0 or x+=+3

Howewer, when substituting 0 for x in original equation, x = 0 proves to be an ENTRANEOUS solution, so the only solution is highlight_green%28x+=+3%29

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