SOLUTION: find equation of a line whose x intercept is-3 and which is perpendicular to the line 3x+5y-8=0

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Question 633429: find equation of a line whose x intercept is-3 and which is perpendicular to the line 3x+5y-8=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept.

line whose x intercept is -3 and which is perpendicular to the line 3x+5y-8=0

3x + 5y - 8 = 0   OR  y+=+highlight%28-3%2F5%29x+%2B+8%2F5

New Line perpendicular to the above:  m = 5/3

 y = (5/3)x + b

 0 = (5/3)·-3 + b   |Using x-intercept = -3:  |(x,y):(-3,0)  to solve for b

 5 = b

 y = (5/3)x + 5