SOLUTION: How do I write the following expression as a single logarithm? {{{3loga-logb-1/2logc}}} thank you

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Question 633359: How do I write the following expression as a single logarithm?
3loga-logb-1%2F2logc
thank you
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Good try at getting the problem to display as you would write it on paper.
I have been working on this website for about a year and do not always get it to show what I want.
I am betting that the problem was not exactly as it shows.
I am betting that the problem was
3loga-logb-(1/2)logc=3loga-logb-(logc)/2 , or
3loga-logb-1%2F2logc=3loga-logb-%28logc%29%2F2
You get to use the following properties of logarithms:
x%2Alog%28y%29=log%28%28y%5Ex%29%29 , log%28x%29%2Blog%28y%29=log%28xy%29 , and log%28x%29-log%28y%29=log%28x%2Fy%29
3loga-logb-1%2F2=log%28%28a%5E3%2F%28%0D%0Ab%2Asqrt%28c%29%29%29%29