SOLUTION: there were studied the effects on the rats fed on a diet that contains 10 % of protein. The protein was consisting in of yeast and cornflour. changing the percentage P of yeast in

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: there were studied the effects on the rats fed on a diet that contains 10 % of protein. The protein was consisting in of yeast and cornflour. changing the percentage P of yeast in       Log On


   



Question 633253: there were studied the effects on the rats fed on a diet that contains 10 % of protein. The protein was consisting in of yeast and cornflour. changing the percentage P of yeast in the miscellany of the above mentioned protein, it was estimated that the weight gained (in grams) of a rat in a period of time, it was f (p), where:

F (p) = - 1/50 P^2 + 2P+ 20... 0 ≤ P≤ 100. Find the máximum- weight.

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
F%28p%29+=+%28-+1%2F50%29P%5E2+%2B+2P%2B+20
As you probably know, the graph of f(p) will be a parabola because of the p squared term. And since the p squared term has a negative coefficient, -1/50, this parabola will open downwards. If you picture such a parabola in your mind (or draw one) it should be easy to see that there is a highest (maximum) point on this parabola, the vertex. So if we find the vertex we will be finding the maximum weight.

How do you find the vertex of a parabola? One way would be to rewrite the equation in vertex form:
4p%28y-k%29+=+%28x-h%29%5E2
Another way to find the vertex is to know and remember that the x-coordinate (or p-coordinate in this case) of the vertex is -b/2a with the "b" and "a" coming from the standard form of the equation of a parabola:
y+=+ax%5E2%2Bbx%2Bc
Since your equation is already in standard form we are going to use -b/2a:
p+=+-%282%29%2F2%28-1%2F50%29
which simplifies to:
p = 50 (which is in the allowed values of 0 to 100)

Of course we have to remember that p is the percent of of yeast, not the maximum weight. To find the maximum wedight we must find f(50):
f%2850%29+=+%28-1%2F50%2950%5E2+%2B+2%2850%29+%2B+20
which simplifies as follows:
f%2850%29+=+%28-1%2F50%292500+%2B+2%2850%29+%2B+20
f%2850%29+=+-50+%2B+100+%2B+20
f%2850%29+=+70
The maximum weight then, is 70 grams (which occurred when the percent of yeast was 50).