SOLUTION: A tugboat goes 140 miles upstream in 10 hours. The return trip downstream takes 5 hours. What is the speed of the tugboat with out a current and what is the speed of the current?

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Question 633217: A tugboat goes 140 miles upstream in 10 hours. The return trip downstream takes 5 hours. What is the speed of the tugboat with out a current and what is the speed of the current?

Found 2 solutions by richwmiller, ewatrrr:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
r*t=d
10(x-c)=140;
5(x+c)=140
x+c=28
x-c=14
2x=42
x=21
x+c=28
21+c=28
c=7


Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Note: D = rt  OR  r = D/t

  r - c = 14 = 140mi%2F10hr

  r + c = 28 = 140mi%2F5hr

   2r = 42

    r = 21   and c = 7  21+%2B+c+=+28