Question 63318: Please solve:
A trapezoid is formed by lines with the following equations:
2x+4y=16, x=4, x=0, y=0
Find the area of the trapezoid. Show all work and explain.
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! Please solve:
A trapezoid is formed by lines with the following equations:
AB SAY 2x+4y=16,BC SAY x=4,DA SAY x=0,CD SAY y=0
Find the area of the trapezoid. Show all work and explain.
SINCE 2 OPPOSITE SIDES SHOULD BE PARALLEL , THEY ARE X=4 AND X=0 IN THE ABOVE.
A IS INTERSECTION OF AB AND DA...HENCE SOLVING AB AND DA
2X+4Y=16
X=0
WE GET
4Y=16
Y=4
HENCE A IS (0,4)
SIMILARLY BIS INTERSECTION OF BC AND AB
B IS (4,2)
C IS INTERSECTION F BC AND CD
C IS (4,0)
D IS THE INTERSECION F DA AND CD
D IS (0,0)
SO AREA OF TRAPEZIUM = 0.5[SUM OF PARALLEL SIDES][DISTANCE BETWEEN PARALLEL SIDES]
A = 0.5[BC+DA][DIST.BETWEEN BC AND DA]
A=0.5[(4-4)^2+(2-0)^2][4-0]
A=0.5*4*4=8 SQ.UNITS
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