SOLUTION: Emma paid the $10.43 bill for her lunch with 236 coins consisting of pennies, nickels, and dimes. If the number of nickels plus the number of dimes was equal to the number of penni
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: Emma paid the $10.43 bill for her lunch with 236 coins consisting of pennies, nickels, and dimes. If the number of nickels plus the number of dimes was equal to the number of penni
Log On
Question 633156: Emma paid the $10.43 bill for her lunch with 236 coins consisting of pennies, nickels, and dimes. If the number of nickels plus the number of dimes was equal to the number of pennies, then how many of each type did she use? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! WE can make several equations.
10d+5n+p=1043;
p+n+d=236;
n+d=p
Now we have three equations with three unknowns and can solve them.
d=67
n=51
p=118