SOLUTION: 1. perpendicular to and bisecting the line segment whose endpoints are A(-1,6) and B(5,-4). the answer is 3x-5y-1=0. what is the solution of it? 2. with slope equal to -1 and x-in

Algebra ->  Formulas -> SOLUTION: 1. perpendicular to and bisecting the line segment whose endpoints are A(-1,6) and B(5,-4). the answer is 3x-5y-1=0. what is the solution of it? 2. with slope equal to -1 and x-in      Log On


   

Question 633147: 1. perpendicular to and bisecting the line segment whose endpoints are A(-1,6) and B(5,-4). the answer is 3x-5y-1=0. what is the solution of it?
2. with slope equal to -1 and x-intercept equal to 6. the answer is x+y-6=0. what is the solution?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

 Line perpendicular to and bisectingthe line segment whose endpoints are A(-1,6) and 

B(5,-4)  m = 10/-6 = -5/3 m+=%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29

And midpointof the  line segment is (2,1)  |Midpoint Pt(x,y):  ( %28x%5B1%5D+%2B+x%5B2%5D%29%2F2, %28y%5B1%5D+%2B+y%5B2%5D%29%2F2++%29)

New Perpendicular Line:

 m = 3/5   | perpendicular lines have slopes that are the negative reciprocal of one another

 y = mx + b

 y = (3/5)x + b

 1 = (3/5)2 + b

 -1/5 = b

y = (3/5)x - 1/5   or  3x-5y -1 = 0



Line with slope equal to -1 and x-intercept equal to 6

 y = mx + b

 y = -x + b   |using ordered pair (6,0) to find b

 0 = -6 + b

 6 = b

y = -x + 6   or x + y-6 = 0