SOLUTION: Write the following as a quadratic equation, Two consecutive odd integers have a product of 35
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Question 633123
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Write the following as a quadratic equation, Two consecutive odd integers have a product of 35
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Denote the first odd number by 2n+1 then the next consecutive odd number is 2n+3. We have (2n+1)(2n+3)=35 so 4*n^2+8n+3=35 so 4*n^2+8n-32=0 so n^2+2n+8=0.