Question 63310: Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Answer by ptaylor(2198)   (Show Source):
You can put this solution on YOUR website! We'll let x=amount of time that will pass before the second cyclist catches up with the first from the time the second cyclist started biking
Now we know that when the 2nd cyclist starts biking, the first cyclist has already traveled (6)(3) or 18 miles and we also know that when the 2nd cyclist catches up, the first cyclist will have traveled 18+6x miles and the 2nd cyclist will have traveled 10x miles. Obviously, when these two distances are equal, the two cyclists are at the same place on the trail and that's what we are looking for. So, the equation to solve is:
18+6x=10x or
18=4x
x=4.5 hours
Hope this helps and have a happy holiday season---ptaylor
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