SOLUTION: solve algebraically: log5+log(4-2x)=log(x-1)

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Question 63303: solve algebraically: log5+log(4-2x)=log(x-1)
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
log5+log(4-2x)=log(x-1)

By the Law of Logarithms:
log 5(4-2x) = log (x-1)

5(4-2x) = (x-1)
20 - 10x = x-1

Add 10x to each side of the equation. Also add +1 to each side:
21=11x

Divide both sides by 11:
x= 21%2F11

The answer is valid, since it does not cause the log of a negative!!
R^2 at SCC