SOLUTION: The perimeter of a standard basketball court is 288 ft. Find the dimension of the basketball court if its length is 44 ft. longer than the width.

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Question 632815: The perimeter of a standard basketball court is 288 ft. Find the dimension of the basketball court if its length is 44 ft. longer than the width.
Answer by lwsshak3(11628) About Me  (Show Source):
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The perimeter of a standard basketball court is 288 ft. Find the dimension of the basketball court if its length is 44 ft. longer than the width.
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let x=length of court
x-44=width of court
twice the length+twice the width=perimeter=288
2x+2(x-44)=288
x+x-44=144
2x=188
x=94
width=x-44=50
dimension of the basketball court: 94 by 50 ft