SOLUTION: You need to prepare 65 mL of a 60% soda/syrup “prescription”. To do this, you can use the 80% soda solution and the syrup solution (0%) that you have in inventory. How many mL of

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: You need to prepare 65 mL of a 60% soda/syrup “prescription”. To do this, you can use the 80% soda solution and the syrup solution (0%) that you have in inventory. How many mL of       Log On

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Question 632783: You need to prepare 65 mL of a 60% soda/syrup “prescription”. To do this, you can use the 80% soda
solution and the syrup solution (0%) that you have in inventory. How many mL of each solution do you
need to create this final solution?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
You need to prepare 65 mL of a 60% soda/syrup “prescription”.
To do this, you can use the 80% soda solution and the syrup solution (0%)
that you have in inventory.
How many mL of each solution do you need to create this final solution?
:
Let x = amt of syrup required
the total result is to be 65 ml, therefore:
(65-x) = amt of 60% soda
:
.80(65-x) = .60(65)
52 - .80x = 39
-.8x = 39 - 52
-.8x = -13
x = %28-13%29%2F%28-.8%29
x = +16.25 ml of syrup required
then
65-16.25 = 48.75 ml of soda solution