SOLUTION: Given the point (-2, -1 and a slope of 3/2 find the equation of the line having this slope and point This is confusing me!!!!!!!!! lackinmath

Algebra ->  Real-numbers -> SOLUTION: Given the point (-2, -1 and a slope of 3/2 find the equation of the line having this slope and point This is confusing me!!!!!!!!! lackinmath      Log On


   



Question 63270: Given the point (-2, -1 and a slope of 3/2 find the equation of the line having this slope and point
This is confusing me!!!!!!!!!
lackinmath

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
First, you must be convinced that knowing
1) a point
2) the slope
of a line determines that line, and therefore
the equation of the line.
First imagine the x-y co-ordinates
Then imagine the x-y plane FILLED with lines of a certain
slope, say 3/2.
Now convince yourself that saying "I only want the line
that goes through the point (-2,-1) eliminates all other lines but one.
Convinced? OK
point-slope formula is
%28y+-+y%5B1%5D%29+%2F%28+x+-+x%5B1%5D%29+=+m%29
where m = slope
and (x[1], y[1]) = (-2,-1)
%28y+-+%28-1%29%29+%2F+%28x+-+%28-2%29%29+=+3%2F2
%28y+%2B+1%29+%2F+%28x+%2B+2%29+=+3%2F2
multiply both sides by 2
%282y+%2B+2%29+%2F+%28x+%2B+2%29+=+3
multiply both sides by x+2
2y+%2B+2+=+3x+%2B+6
2y+=+3x+%2B+4
y+=+%283%2F2%29x+%2B+2
now check it
It does have slope = 3/2, since it's in the form
y = mx + b
Does it go through (-2,-1)?
-1+=+%283%2F2%29%2A%28-2%29+%2B+2
-1+=+-3+%2B+2
-1+=+-1
OK