SOLUTION: Can you please help with this word problem. Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were inc

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Question 63234: Can you please help with this word problem.
Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
1. +.05n+%2B+.10d+=+5.65+
2. +.05%28n%2B8%29+%2B+.10%282d%29+=+10.45+
solve equation 1 for nickles
+.05n+%2B+.10d+=+5.65+
+.05n+=+5.65+-+.10d+
divide all parts by .05
+n+=+113+-+2d+
substitute this back into equation 2
+.05%28n%2B8%29+%2B+.10%282d%29+=+10.45+
+.05%28113-2d%2B8%29+%2B+.10%282d%29+=+10.45+
combine like terms
+.05%28105-2d%29+%2B+.10%282d%29+=+10.45+
distribute
+5.25+-+.1d+%2B+.2d+=+10.45+
add like terms
+5.25+%2B+.1d+=+10.45+
subtract 5.25 from both sides
+.1d+=+5.20+
divide by .1
+d+=+52+
He has 52 dimes