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Question 632187: The product of two consecutive even integers is 18 less than 9 times their sum. Find the two integers.
Answer by dfrazzetto(283)   (Show Source):
You can put this solution on YOUR website!
2n, 2n+2
(2n)(2n+2) = 9(2n+2n+2) - 18
4n^2 + 4n = 9(4n + 2) - 18
4n^2 + 4n = 36n + 18 - 18
4n^2 + 4n - 36n = 0
4n^2 - 32n = 0
4n(n - 8) = 0
n = 0, 8
two sets of consecutive even integers:
{0,2}
{16,18}
check:
16*18 = 9(16+18) - 18
288 = 9(34) - 18
288 = 306 - 18
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