SOLUTION: Find two consecutive even integers whose product is 72. Find two consecutive even integers whose product is 168.

 

Hi,

Find two consecutive integers,  whose product is 72.

 x(x+1) = 72

 x^2 + x - 72 = 0

(x+9)(x-8) = 0 , x = -9  or x = 8

two consecutive integers are:  -9, -8   or  8, 9

There are no  two consecutive even integers whose product is 72



Find two consecutive even integers , whose product is 168. 

 x(x+2) = 168

 x^2 + 2x - 168 = 0 

(x+14)(x-12) = 0. x = -14   or x = 12

two consecutive even integers are:  -14, -12   or 12, 14