eq. 1 x+xy+1=16
eq. 2 x-y=1,
Solve eq. 2 for x:
eq. 2 x-y=1
eq. 3 x=1+y
Substitute 1+y for x in eq. 1:
eq. 1 x+xy+1=16
(1+y)+(1+y)y+1=16
1+y+y+y²+1=16
y²+2y+2=16
y²+2y-14=0
Two solutions for y:
and
Use eq. 3 with first solution for y
x=1+y
x=1+
x=
First solution:
then x+y=+()
then x+y=
Use eq. 3 with second solution for y
x=1+y
x=1+
x=
Second solution:
then x+y=+()
then x+y=
Edwin