SOLUTION: The perimeter of a rectangle is (4x^2 +8x +18) inches and its length is (x^2 + 3x + 6) inches. find its width

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is (4x^2 +8x +18) inches and its length is (x^2 + 3x + 6) inches. find its width      Log On


   

Question 631852: The perimeter of a rectangle is (4x^2 +8x +18) inches and its length is (x^2 + 3x + 6) inches. find its width
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is P=2%28l%2Bw%29
where l is the length, w is the width of a rectangle
Therefore
%284x%5E2+%2B8x+%2B18%29=2%28x%5E2+%2B+3x+%2B+6%2Bw%29 divide by 2
2x%5E2%2B4x%2B9=x%5E2%2B3x%2B6%2Bw Solve for w
w=%282x%5E2%2B4x%2B9%29-%28x%5E2%2B3x%2B6%29
w=2x%5E2%2B4x%2B9-x%5E2-3x-6
w=x%5E2%2Bx%2B3