Question 631827: 1)Find the sum of the arithmetic sequence 2, 4, 6, 8, ..., 70.
2)Find the sum of the geometric sequence 42, 7, 7/6, .... , 42(1/6)^8
3)find the sum of the first n terms of the sequence. The sequences are either arithmetic or geometric. -1, 11, -121, ...; n = 9
4)find the sum of the first n terms of the sequence. The sequences are either arithmetic or geometric. 14, 8, 2,...; n=9
Answer by ewatrrr(24785) (Show Source):
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Hi,
Arithmetic sequence
In General: and 
{2, 4, 6, 8, ..., 70) d = 2 and n = 35
finding the Sum of the first 35 Terms: 
14, 8, 2,...; n=9 d = -6
finding the Sum of the first 9 Terms:
Geometric sequence
In General: and 
Find the sum of the geometric sequence 42, 7, 7/6, .... , and last term is the 9th Term
finding the Sum of the first 9 Terms: using as is so insignificant
-1, 11, -121, ...; n = 9 , r = -11 :
finding the Sum of the first 9 Terms: 
will Let You finish this one out
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