SOLUTION: A squirrel is running along a branch 144 feet above ground dislodges a pine cone. After how many seconds does the pine cone land on the ground? (assume no branches interfere with i

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Question 631807: A squirrel is running along a branch 144 feet above ground dislodges a pine cone. After how many seconds does the pine cone land on the ground? (assume no branches interfere with its fall).
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Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
As the pine cone falls, its downwards velocity increases linearly (starting from zero) at an acceleration of 32 ft/s^2 (32 ft per second every second).
In general, acceleration is represented by the letter a.
(The acceleration due to gravity on the surface of planet Earth is often represented by the letter g, and we know it is g=3.2ft%2Fs%5E2).
The distance d traveled by an object starting at rest and accelerating at a constant acceleration a for a time t is given by
d=at%5E2%2F2
In this case, d=gt%5E2%2F2
We know d=144 feet, we know g=3.2ft%2Fs%5E2), and we want to know t , which we will get in seconds.
We can substitute first to get
144=32t%5E2%2F2 and then solve.
144=32t%5E2%2F2 --> 144%2A2=32t%5E2 --> 144%2A2%2F32=t%5E2 --> 9=t%5E2
The solution that makes sense (we do not expect a negative time) is
t=sqrt%289%29 --> t=3 --> highlight%28t=3%29 seconds.