SOLUTION: Given that a parabola has a directrix of y=-3.25 and focus (0,-2.75), find the vertex. then write an equation of the parabola then graph the parabola please show all work

 

Hi

the vertex form of a Parabola opening up(a>0) or down(a<0),  

where(h,k) is the vertex  and  x = h  is the Line of Symmetry

The standard form is , where  the focus is (h,k + p)

and  length of  the  latus rectum 

directrix of  y= -3.25 and focus (0,-2.75), 

y-value of Midpoint between directrix and focus is -6/2 = -3 , p = .25  and 4p = 1  V(0,-3)

   or